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How To Solve 2X Y 4

Input interpretation solve (2 X) Y×4 = 0

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How To Solve 2^X = 8

Input interpretation solve 2^X = 8 Result X = (log(8) + 2 i pi n)/log(2) and n element Z Real solution X = 3

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How To Simplyfy Radicals

Input interpretation simplify | sqrt(1 + 2 x + x^2) Result sqrt((x + 1)^2) Alternate form assuming x is real abs(x + 1) Alternate form assuming x>0 x + 1

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How To Simply Radicals

Input interpretation Calculus and Analysis > Special Functions > Radicals Topics casus irreducibilis | cube root | nested radical | nested radical constant | Newton’s iteration | nth root | principal root of unity | principal square root | Pythagoras’s constant | quadratic surd | radical | Ramanujan log-trigonometric integrals …

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How To Simplifying Radicals

Input interpretation simplify | sqrt(1 + 2 x + x^2) Result sqrt((x + 1)^2) Alternate form assuming x is real abs(x + 1) Alternate form assuming x>0 x + 1

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How To Simplify The Square Root Of 80

Input interpretation simplify | sqrt(80) Result 4 sqrt(5) Decimal approximation 8.944271909999158785636694674925104941762473438446102897083…

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How To Solve A Quadratic Equation With The Quadratic Formula

Input interpretation quadratic formula Equation x^2 – 2 x + 1 = 0 a x^2 + b x + c = 0 | x | indeterminate variable a | quadratic coefficient b | linear coefficient c | constant coefficient (x = (-b ± sqrt(b^2 – 4 a c))/(2 a)) Input …

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How To Solve A Quadratic Equation By Completing The Square

Input interpretation complete the square | 28 + 10 x + x^2 Result (x + 5)^2 + 3 Geometric figure parabola Polynomial discriminant Delta = -12 Derivative d/dx((x + 5)^2 + 3) = 2 (x + 5) Indefinite integral integral (3 + (5 + x)^2) dx = x^3/3 + 5 …

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How To Solve A Quadratic Equation Using The Quadratic Formula

Input interpretation quadratic formula Equation x^2 – 2 x + 1 = 0 a x^2 + b x + c = 0 | x | indeterminate variable a | quadratic coefficient b | linear coefficient c | constant coefficient (x = (-b ± sqrt(b^2 – 4 a c))/(2 a)) Input …

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How To Solve A Geometric Series

Infinite sum sum_(k=0)^infinity x^k = 1/(1 – x) when abs(x)

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